Question

Correct me if i'm right {n^2 e^-n}
i think this result is diverge

Answer 1

N0
\[
\frac {n^2}{e^n}
\]
Apply L'Hospital Rule to see that the sequence converges to zero.

Answer 2

ok let me c

Answer 3

if we use zero then is 0^2/e^0 = 0/1=0

Answer 4

Apply it near \[ n=\infty\]

Answer 5

you get
\[
\frac {\infty} {\infty}
\]

Answer 6

lim of n-> infty

Answer 7

yes

Answer 8

k thx