Can somebody help me with Bernoulli Trials?
ask!
The question asks: Consider tossing a fair die 16 times. Find the value or values of k such that the probability the number 2 comes up exactly k times is as large as possible. i said (n+1)p = 17/6 so k =\[\lfloor 17/6 \rfloor\] and i was marked wrong
so if X is the number of twos you see, you want to maximimize \[P(X=k)\] right?
i think k stands for number of trials so after how many trials will two have the highest probability?
the probability you get k twos in 16 trials is \[\dbinom{16}{k}(\frac{1}{2})^{16}\] right?
so the question boils down to "what is the k that maximized \(\binom{16}{k}\)?"
oh crap i was thinking about coins hold on that is utterly wrong!!!
you want to maximize \[\dbinom{16}{k}(\frac{1}{6})^k(\frac{5}{6})^{16-k}\]
yeah but that's basically it with dice. for what k will the prob. be greatest. my textbook said something along the lines of (n+1)p
sorry ignore first post it was way off
but i put that and got it wrong
well let us check i am not sure what your answer means, but it should be 2 or three
i forget, is it floor \(\frac{17}{2}=2\) or ceiling \(\frac{17}{2}=3\)?
what did you write as an answer? your number needs to be an integer
7 since it was\[\lfloor 17/6 \rfloor\]
i mean 2***
oh ok lets check
\[P(X=2)=.2566\] \[P(X=3)=.2423\] so it looks like you are a winner
hmm i guess my professor made a mistake by marking me wrong i will have to speak with him but thanks for helping! =D
oh but you said you were marked wrong. i would put that down to human error, not your error
yeah say very politely "i went over my exam to check all my mistakes and make sure i understood the material, but when i checked my answer i looked like i was correct? can you help explain?"
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