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HELP ME. Enter the quadratic equation in standard form. x^2-4x-29=-10
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standard form -> ax^2 + bx + c = 0
add 10
just make the right side zero then you're all set
by doing that
x^2 - 4x -29 + 10 = 0 => x^2 - 4x - 19.
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\(\Large \color{purple}{\rightarrow x^2 + 4x + 29 = 10 }\) Multiply both sides by -1 and you get the answer.
You can also subtract 29 from both sides.
I've done my job @pratu043 @satellite73 @lgbasallote
Or subtract 10 from both sides.
@ParthKohli you can NOT subtract 29 from both sides...like i stated standard form is ax^2 + bx + c = 0 so the right side MUST be zero...just clearing your misconception
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So subtract 10?
yup only way
So the actual answert is?...
Use my way, just don't do that 29 thingy. Multiply -1 to both sides.
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