HELP ME.
Enter the quadratic equation in standard form.
x^2-4x-29=-10

Question

HELP ME. 
Enter the quadratic equation in standard form. 
x^2-4x-29=-10

lgbasallote · Answer

standard form -> ax^2 + bx + c = 0

anonymous · Answer

add 10

lgbasallote · Answer

just make the right side zero then you're all set

lgbasallote · Answer

by doing that

anonymous · Answer

x^2 - 4x -29 + 10 = 0
=> x^2 - 4x - 19.

parthkohli · Answer

$\Large \color{purple}{\rightarrow x^2 + 4x + 29 = 10 }$

Multiply both sides by -1 and you get the answer.

parthkohli · Answer

You can also subtract 29 from both sides.

parthkohli · Answer

I've done my job @pratu043 @satellite73 @lgbasallote

anonymous · Answer

Or subtract 10 from both sides.

lgbasallote · Answer

@ParthKohli you can NOT subtract 29 from both sides...like i stated standard form is ax^2 + bx + c  = 0 so the right side MUST be zero...just clearing your misconception

parthkohli · Answer

So subtract 10?

lgbasallote · Answer

yup only way

anonymous · Answer

So the actual answert is?...

parthkohli · Answer

Use my way, just don't do that 29 thingy. Multiply -1 to both sides.