Question

3. Solve: 2x^2 – 18x + 28 = 0

Answer 1

use quadratic formula..

Answer 2

I dont know how.

Answer 3

\[-b \pm \sqrt{b ^{2}-4ac}/2a\]

Answer 4

take 2 common from ur equation:
\[2x ^{2}-18x+28\]
2(x^2-9x+14)
so ur a=1; b=-9; c=14

Answer 5

\[-(-9)\pm \sqrt{(-9)^{2}-4(1)(14)}/2(1)\]