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Mathematics 19 Online
OpenStudy (anonymous):

y=nlog(n) => find n=f(y)

OpenStudy (anonymous):

x=log_a z means z = a^x

OpenStudy (anonymous):

function is x-> x * log x

OpenStudy (anonymous):

So?

OpenStudy (anonymous):

well it is not x->log x

OpenStudy (anonymous):

Just transform it as usual

OpenStudy (anonymous):

sorry I don't see what you're trying to do :/

OpenStudy (anonymous):

n log n is log n^n

OpenStudy (anonymous):

yep but then i've n^n=e^y

OpenStudy (anonymous):

\[x=\frac{y}{\Omega(y)}\] It seems that it is something like that. ^^

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