Question

a body is thrown vertically upwards from a wall oh height 2.2m with a speed of 10m/s the distance travelled in the last second of its motion is (g=10m/s^2)

Answer 1

s=ut+1/2at^2
-2.2 =10t-1/2*10*t^2
50t^2-100t-22=0
25t^2-50t-11=0
t^2-2t-11/25=0
t^2-2t+1=11/25+1
(t-1)^2=36/25
t-1=+/-6/5
t=6/5+1
t=11/5
v=u+at
0=10-10t1
10=10t1
t1=1
t2=11/5-1
=6/5
d=0+10(6/5-1/2)
=10((12-5)/10)
=7