Question

Write the slope-intercept equation for the line that passes through (-8, -10) and is perpendicular to -8x – 3y = -16

Answer 1

slope intercept form is
y=mx+b
you need to put the given eq in this form in order to begin

Answer 2

I don't know what you mean. :/

Answer 3

put -8x-3y=-16 into slope intercept form

Answer 4

I really am not sure how to do that.

Answer 5

can you turn the manipulate the equation algebraically to get y on the left side and x and whatever else on the right side

Answer 6

The gradient of the equation given:
-8x-3y=-16
8x+3y=16
3y=16-8x
y=16/3-(8/3)x
gradient =-8/3

For two line which is perpendicular,both gradient is multiply each other =-1
m1m2=-1
Therefore gradient for the answer is 3/8

y=(3/8)x+c

to find c(y-intercept)
sub x= -8 y=-10 into the equation

-10=-3+c
c=-7

So the equation is y=(3/8)x-7

Answer 7

thank you!!