find the slope and y intercept of the line in the given equation. y=-2/7x-3
when an eqaution is in this form (y=mx+b), the number multiplying the x is the slope. Y intecept is where x =0. so plug in 0 for x and evaluate
so?
so what's the slope?
would be 7 or 3
im new to this algebra so Im trying to understand
for the slope use this equation slope = m m = (y2 - y1)/(x2-x1) to find the y intercepts set x = 0 and solve for y you will get (0,y) you will only get one or no y-intercepts for the x-intercepts set y = 0 and solve for x you will get (x,0) you can have more than one solution (more than one point) in some cases
there solved
so would I graph this
also for the slope equation (x1,y1) and (x2,y2) are two points in the function (equation) you are looking at so for y=-2/7x-3 just sub values into x and solve for y to acquire points then use the equation for the slope I showed you to solve for the slope
you dont have to graph it you can just use the formula I provided, sub two numbers into the equation in place of x and solve for y to get two points to find the slope.
the equation being what is refereed to as a function
referred*
Also note in some cases you will have no x intercepts for example 2^(x) = y y can never equal 0 thus you will never have any x intercepts the graph looks like this |dw:1336842595608:dw| it will come infinity close to zero on the x-axis but never reach it
im sorry im just not sure how to write it
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