Question

.

Answer 1

d=length of diagonal
w=\[\sqrt{d^2-9^2}\], h=\[\sqrt{d^2-16^2}\]

Answer 2

Those equations are right. For every value of d, there's going to be a different value of h. Which means that ratio of length to width won't be the same.

Answer 3

Here's what we know. \[d^2=l^2+h^2\] and \[{9\over16}={h \over l}\]
So we have \[l^2=d^2-\left( 9l \over16 \right)^2\]
So now...\[l=\sqrt{256d^2\over337}\] you can use same method to express \[h\]as a function of\[d\]