Question

find the area of the triangle whose sides have the given lengths.
a=9, b=12, c=15

Answer 1

Do you know Heron's formula @Chiomatn93 ? Apply that and you will get your answer

Answer 2

http://en.wikipedia.org/wiki/Heron%27s_formula

Answer 3

\[s= (9+12+15)/2 =18
now by heron's formula
Area=\sqrt{18* (18-9) (18-12)(18-15)}\] \
[\sqrt{18*9*6*3} = \sqrt{2916} = 54

therefore your area is 54

Answer 4

whats the answer and how do u solve?

Answer 5

Answer is 54

Answer 6

@Chiomatn93 , Didn't you see the wiki link I gave above ?

Answer 7

how do u solve it though? like the steps???

Answer 8

Commo'n the formula is there, the quantities are given. Now can't you multiply and take the square root by yourself

Answer 9

See
the formula is
\[Area = \sqrt{s(s-a)(s-b)(s-c)}\]
where \[s= {a+b+c \over 2}\]

where a , b, c are the length of the sides of the triangle.
First find s. then substitute to get your Area ??

Answer 10

damn calm down...jeez i will do but i just want an example

Answer 11

see my reply solution is there

Answer 12

wheres the answer?

Answer 13

Ok first you would have to take out the s that is semi perimerter
formula for s is
S= (a +b +c)/2
here the S is 18
Area of triangle is \[A=\sqrt{s*(s-a)*(s-b)*(s-c)}\]
So the area would be now
\[A=\sqrt{18*(18-9)*(18-12)*(18-15)}\]
\[A=\sqrt{18*5*6*3}\]
\[A=\sqrt{2916}\]
A=54
Therefore the area of triangle is A=54 which is your answer

Answer 14

I cannot put it more simply

Answer 15

thank you! i understand it much more now!