use a system of equations in two variables solve the following problem: 3 times a first number increased by twice a second number is 21. The difference between the first number and the second number is 2. Find the number?

Question

anonymous · Answer

3x+2y=21
x-y=2

would be the equations, with x as the first number and y the second number.  But 'Find the number' does not tell us which number you desire.

anonymous · Answer

If you multiply the second equation by 2 then
3x+2y=21
2x-2y=4
and add
5x=25
therefore x=5, subing into the second equation y=3

So the first number is 5 and the second number is 3.

anonymous · Answer

thanks for the steb by step