Question

use a system of equations in two variables solve the following problem: 4 times a first number decreased by 3 times a second number is 22. The sum between the first number and twice the second number is 0. Find the number?

Answer 1

first number = x
second number = y

so you have the equations:
4x - 3y = 22
x + 2y = 0

Answer 2

Which number is it asking you to find? The first or the second?

Answer 3

I have to get numbers for both

Answer 4

Ok then lets solve for x first:
4x - 3y = 22
+3y
4x = 22 + 3y
/4
x = 5.5 + 0.75y

Now substitute the value of x into the second equation:
x + 2y = 0
(5.5 + 0.75y) + 2y = 0
Now you combine the like terms:
5.5 + 0.75y + 2y = 0

Answer 5

When you combine 5.5 + 0.75y + 2y = 0 you'll get the value of y.

Answer 6

So what do you get when you solve fore y in:
5.5 + 0.75y + 2y = 0

Answer 7

I get -2

Answer 8

and for x i get 4 is this all correct?

Answer 9

Thanks you if so.

Answer 10

Yep your're right!:D No problem:)