Question

I don't understand this: if 'y' is y=sqrt x-3, which integer, positive value could x not take?
Could it be 1, or 2?

Answer 1

\[y= \sqrt{x-3}\]
This is the expression

Answer 2

remember that in square roots the radicand (the expression IN the square root) cannot be negative, in other words greater than 0, so... we can say that\[x-3>0\] solve for x

Answer 3

Okay

Answer 4

lol..that was a late medal? =))