find the limit:

Question

find the limit:

anonymous · Answer

$$\lim_{x \rightarrow 0} \sin 3x/2x$$ Also i know that sinx/x=1 is that relevant

anonymous · Answer

yes, but do you know why  lim sinx/x=1? That will get you there.

anonymous · Answer

i don't i just remember thats a special property

anonymous · Answer

a nudge in the right direction?

kropot72 · Answer

You can find the limit by as follows:
1) Express sin3x as an expansion in series up to say the fifth term.
2) Divide each term of the series expansion by 2x.
3) You can easily find the limit at this point

anonymous · Answer

i'm not sure i understand about series. what do you mean?

kropot72 · Answer

The series expansion of f(x) can be found from Maclaurin's theorem:$$\sin x=x-\frac{x ^{3}}{3!}+\frac{x ^{5}}{5!}-\frac{x ^{7}}{7!}+....$$

anonymous · Answer

i've never learned any of this

anonymous · Answer

is there another way to do it?

anonymous · Answer

nevermind i'l just skip these questions