Question

plzz view ??

Answer 1

plzz ans q 143 and 144

Answer 2

143 =2.5

Answer 3

s u r correct steps plzz

Answer 4

can u take a photo of ur work

Answer 5

let me try other 1 first..

Answer 6

ok

Answer 7

use h=ut1+0.5 gt1^2
and -h=ut2-0.6gt2^2
find t1 and t2 and take ratio...
u will need the condition that u=sqrt(2gh)
where h is half height of tower..

Answer 8

-h=ut2-0.6gt2^2??? how 0.6gt^2

Answer 9

for 143
it takes ball insider pillar 1 sec to fall(using h=0.5at^2) so other must also fall i 1 sec...
use -h=ut-0.5gt^2
where t=1,h=pillar height,a=5
u ,to find...

Answer 10

??

Answer 11

u=sqrt(2gh)

Answer 12

use h=ut1+0.5 gt1^2
and -h=ut2-0.6gt2^2
find t1 and t2 and take ratio...
u will need the condition that u=sqrt(2gh)
where h is half height of tower..

Answer 13

here u1 and u2 t1 and t2 are not given

Answer 14

we cant cut them too the ans = 3+2root2

Answer 15

the ball thrown above...
apply 3rd equation of motion
v^2 = u^2 + 2*a*s
u1=u2=u we dont need numerical values
t1 ,t2 are to be found in terms of u from where in ratio the u will cancel out..

Answer 16

how will we use v^2 = u^2 + 2*a*s if we need to find the rato of time

Answer 17

v=0;it gives...
u=sqrt(2gh)

Answer 18

find t from the other two equations that i gave...

Answer 19

i mean t1 and t2..

Answer 20

@shivam_bhalla plz help

Answer 21

i didnt understand what quarkine wrote q 143

Answer 22

for 143
it takes ball insider pillar 1 sec to fall(using h=0.5at^2) so other must also fall i 1 sec...
use -h=ut-0.5gt^2
where t=1,h=pillar height,a=5
u ,to find...

Answer 23

h is not given and u is also not given how to find u???

Answer 24

can anyone answer it plzz

Answer 25

@shameer1 you wrote "h is not given and u is also not given how to find u???"

well, h IS given, it is 2.5 metres. So you know everything but u. Solving for u is easy : linear equation.

Answer 26

i did nt see plzz solve q 144

Answer 27

for vertical height, use
h=1/2at^2
and find t
then use h=ut-1/2gt^2 to find u

Answer 28

i hope you understand how and why i used these equations.

Answer 29

plzz q 144

Answer 30

put the 'T' of both upward and downward in ratio

Answer 31

what do you think can the equation be?

Answer 32

@shameer: what have YOU written so far?

Answer 33

shameer has done nthing much on this qn frm what i hav jst read .....guys pls make him wrk on thew qn and be careful nt to spill out the full answwer in one go :) thanks

Answer 34

\[\huge "No\;\; pain\;\; No\;\; Gain\;!!"\]