Question

how can we prove that:--

Answer 1

prove what??

Answer 2

\[z*z'=|z|^2\] where z= complex no.

Answer 3

Take z = x+ iy
Then
z' = x-iy

Also we know that

|z| = sqrt(x^2 + y^2)

Substitute and solve

Answer 4

let \(z = a + ib \) then \(z' = a - ib \)
multiply them ,,, you will get a^2 + b^2 ... which is |z|^2

Answer 5

You will get LHS = RHS

Answer 6

k! but is there no short method?

Answer 7

k!k! i have understood it. thanx to both of u:)

Answer 8

hope i could give u both medals

Answer 9

yw :)