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Mathematics 19 Online
OpenStudy (maheshmeghwal9):

Prove the following result :----

OpenStudy (maheshmeghwal9):

\[|z^2|=|z|^2\]; Where {z}= complex number.

OpenStudy (anonymous):

\[ z = |z| e^{ i Arg z}\\ z^2 = |z|^2 e^{ 2 i Arg z}\\ |z^2| =|z|^2 \left| e^{ 2 i Arg z}\right|= |z|^2 \]

OpenStudy (maheshmeghwal9):

thanx! I got it.

OpenStudy (anonymous):

yw

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