Question

how to do this? from 0 to 2 integral ▏t-t^2▕ dt=

Answer 1

Split it into 2 integrals one form t =0 to t=1 and one from t=1 to t=2

Answer 2

is the answer -3 ? not sure ?

Answer 3

\[
\int_0^1 ( t -t^2) dt + \int_1^2 (-t + t^2)dt
\]

Answer 4

The first of my integrals above is
\[
\frac 1 6
\]
and the second is

\[
\frac 5 6
\]
So the sum is 1.

Answer 5

The answer is 1.
The answer cannot be < 0, since the absolute value function is >=0