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Mathematics 12 Online
OpenStudy (anonymous):

major help please Andre made a wax model of a rolling pin of diameter 4 cm. The rolling pin was shaped like a right circular cylinder with a right circular cone at each end as shown below. What was the total surface area of the rolling pin? Using complete sentences, describe the steps you used to calculate the surface area.

OpenStudy (anonymous):

OpenStudy (dumbcow):

lateral surface area equations cylinder: \[SA = 2\pi r*h\] cone: \[SA = \pi r*l\]

OpenStudy (dumbcow):

radius = 2 height = 13 slant height = 7

OpenStudy (anonymous):

ok.. ;/

OpenStudy (anonymous):

so you do one multiply it by two then do the cylindar

OpenStudy (dumbcow):

correct, you need surface area of 2 identical cones and the cylinder

OpenStudy (dumbcow):

total surface area will then be: \[2 \pi r*h + 2 \pi r*l = 2 \pi r(h+l)\]

OpenStudy (anonymous):

does it matter if its a right circular cylindar

OpenStudy (dumbcow):

no it doesn't matter...it works for all cylinders

OpenStudy (anonymous):

@dumbcow can you please just concentrate it into an answer.

OpenStudy (anonymous):

251.33cm^2

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