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Mathematics 25 Online
OpenStudy (anonymous):

Eric tossed a coin ten times. The first six tosses resulted in five heads and one tail. What is the probability that the final four tosses will be all tails? Explain.

OpenStudy (anonymous):

should it still be a half?

OpenStudy (anonymous):

1/2^4=1/16

OpenStudy (anonymous):

independent !!

OpenStudy (anonymous):

What does ^ mean? I don't get how the answer is 1/16. I'm only in 7th grade and we haven't learned this. lol

OpenStudy (accessdenied):

Does the flipping of those previous coins affect the outcomes of the next four coins?

OpenStudy (accessdenied):

If we look at it this way, each coin toss has two outcomes of equal probability. The chances of getting a tails once is of course 1/2. Then, we look at getting two tails in a row. I think this outcome tree helps. Each branch represents a possible outcome, so we can count the number of outcomes at the end for the total. |dw:1337034153085:dw| We can see that there are four possible outcomes on the second level of branches, so the chance of getting a T and then another T is 1/4, which is 1/2 * 1/2 (the chance of getting tails times the chance of getting tails)

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