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how do i solve for x? 25^(2x) = 125^(x+2)
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\[25=5^{some power}\] what is that power?
\[125=5^?\] also want to write 125, as 5^?
So if we can write both sides having the same base, all we need to do is set the exponents equal
\[\text{ what is } 5^2?\] \[\text{ what is } 5^3 ?\]
5^2 = 25 5^3 = 125
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yeah so we can do the following : \[(5^2)^{2x}=(5^3)^{x+2}\]
\[5^{2 \cdot 2x}=5^{3(x+2)}\]
so the bases are the same set the exponents equal to each other and solve for x
k, thanks
does x= 6
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\[2 \cdot 2x=3(x+2)\] \[4x=3x+6\] \[4x-3x=6\] \[1x=6 \] \[x=6\]
yep
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