Question

solve:
\[\large \frac{3z_3 - 6z_2}{z_1}\] when \[\large z_1 = 3\sqrt3 + 3i \quad z_2 = -1 + \sqrt{3i} \quad z_3 = 2 - 2\sqrt{3i}\]

Answer 1

you mean simplify?

Answer 2

i mean evaluate :P

Answer 3

Lgba, multiply and divide by z_1

Answer 4

heh?

Answer 5

\[\frac{3(2−2√3 i)- 6(−1+√3i)}{3√3+3i}* \frac{3√3+3i}{3√3+3i}\]

Answer 6

Doing this, your denominator becomes real number

Answer 7

i see

Answer 8

oops

Answer 9

It should be
\[\frac{3(2−2√3 i)- 6(−1+√3i)}{3√3+3i}* \frac{3√3-3i}{3√3-3i}\]

Answer 10

ill take it from here thanks :D

Answer 11

yw :)