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ok for number 11 use the distance formula \[d=\sqrt{(x2-x1)+(y2-y1)2}\] sub both A(-1,0) and B(5,8) into that equation.
and number 12 u use the midpoint formula (x1+x2)/2 (y1+y2)/2 to get x value y value
the only steps u have to do are sub in the correct values into the formulas.
ok for question 11 \[d= \sqrt{((5-(-1))^2+(8-0)^{2}}\] \[d= \sqrt{6^{2} + 8^{2}}\] \[d = \sqrt{36 + 64}\] \[d=\sqrt{100}\] d = 10
when i stated the distance between two formulas b4 i forgot the ^2 around the x^2 bracket but the working out is correct.
so for question 12 a(-1,0) and b(5,8) \[(-1+5)/2\] and \[(0+8)/2\] 4/2 8/2 2 4 x-value y-value so mid point is at the coordinates (2,4)
omg. i love you. thank you so much.
haha it's okay. as long as u understand how to do it :)
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