Question

log10^2 +16log10^16/25+12log10^25/24+7log10^81/80+log10^25/49+2log10^7 =?

Answer 1

the ans=2log5+1

Answer 2

@TuringTest plzz help

Answer 3

try moving all factors of logs to exponents, then exponentiate and simplify?

Answer 4

I will work it this way and see where it takes me. :)

Answer 5

i did but not getting dude plzz can u show me

Answer 6

When I work it through, I will.

Answer 7

\[log10^2 +16log10^{\frac{16}{25}}+12log10^{\frac{25}{24}}+7log10^{\frac{81}{80}}+log10^{\frac{25}{49}}+2log10^7 \]
Is this the question?

Answer 8

yes

Answer 9

is it log base 10 of 10^apower

Answer 10

but the ans=2log5 + 1

Answer 11

\[log10 =1\]\[logx^a= alogx\]

\[log10^2 +16log10^{\frac{16}{25}}+12log10^{\frac{25}{24}}+7log10^{\frac{81}{80}}+log10^{\frac{25}{49}}+2log10^7 \]\[=2log10 +16(\frac{16}{25})log10+12(\frac{25}{24})log10+7(\frac{81}{80})log10+(\frac{25}{49})log10+2(7)log10 \]\[=2 +16(\frac{16}{25})+12(\frac{25}{24})+7(\frac{81}{80})+(\frac{25}{49})+2(7) \] \[Can \ you \ do \ it ? \]

Answer 12

then the answer wont be 2log5 +1

Answer 13

Oh... then either the question you posted is incorrect,
or the answer you've looked at is incorrect...

Answer 14

oh........ it is log 2 to the base 10 and ............go o n all other too

Answer 15

._. That's totally different......

Answer 16

\[log_{10}2?\]

Answer 17

yaa

Answer 18

\[log_{10}2 = log2\]

Answer 19

I am at
10^x=2+(16/25)^16+(25/24)^12+(81/80)^7+25/49+7^2
have you tried this approach yet?

Answer 20

how log10^2=log2

Answer 21

log is assumed base ten unless otherwise specified.

Answer 22

Wait
is it \[log10^2 \ or \ log_{10}2?\]

Answer 23

log with a base 10 is common log, usually, we omit the base 10... and write log 2 directly

Answer 24

or......... is the question

Answer 25

i am unable to write the equation it is not log 10 square the other one is the question

Answer 26

could you scan the problem and post it as image? just so we are all clear on the problem

Answer 27

\[log2^2 +16log2^\frac{16}{25}+12log2^\frac{25}{24}+7log2^\frac{81}{80}+log2^\frac{25}{49}+2log2^7 \]Is this the question?

Answer 28

log with a base 10 is common log, usually, we omit the base 10... and write log 2 directly this is correct

Answer 29

this is the question.

Answer 30

\[log2^2 +16log2^\frac{16}{25}+12log2^\frac{25}{24}+7log2^\frac{81}{80}+log2^\frac{25}{49}+2log2^7 \]\[=2log2 +16(\frac{16}{25})log2+12(\frac{25}{24})log2+7(\frac{81}{80})log2+(\frac{25}{49})log2+2(7)log2 \]\[=[2 +16(\frac{16}{25})+12(\frac{25}{24})+7(\frac{81}{80})+(\frac{25}{49})+2(7) ]log2 \]Can you simplify it first and tell me what you've got?

Answer 31

Anyway, It won't give the answer you provided lol

Answer 32

u got the question wrong

Answer 33

log10^2 the 10 is base and 2 is the exponent eg log2^8=3

Answer 34

now u got it.........

Answer 35

Is that my fault again?
I've interpreted your question twice and every time you said they are correct..
Now you're telling me that I'm wrong..

Answer 36

It is \[log_28 = log_22^3 = 3log_22 = 3\]

Answer 37

You've never told us what exactly the question is..

Answer 38

Can you scan us the question? I don't want to interpret it again.. I've been typing similar things for twice..

Answer 39

ys this is the question

Answer 40

i will draw