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Chemistry 13 Online
OpenStudy (anonymous):

0.3660g of a metallic sulphide was roasted in air to yield the oxide of the metal along with SO2 which was passed into bromine water the solution was boiled cooled and treated with barium chloride solution 0.875g of BaSO4 was obtained calculate the equivalent weight of the metal (ba=137.4)

OpenStudy (anonymous):

the ans=~32.8 plz solve it

OpenStudy (anonymous):

@Kryten plz help

OpenStudy (anonymous):

can someone help me plzz

OpenStudy (anonymous):

are you 100% sure the right answer is 32.8 ?

OpenStudy (anonymous):

yes the ans is ~32.8

OpenStudy (anonymous):

32.8 represents the molecular weight of the metal, so your metallic sulphide is one of these: CdS, PbS, MoS2, Na2S, ZnS, SeS2, FeS2, but none of those metals has a molecular weight of 32.8...

OpenStudy (anonymous):

it is asked to find the equivalent weight

OpenStudy (anonymous):

@Kryten plzzz help

OpenStudy (anonymous):

@heena plzz help

OpenStudy (anonymous):

ok i ll tell u the steps first write the balanced reaction and show me

OpenStudy (anonymous):

wat is bromine water ?

OpenStudy (anonymous):

@open_study1 Here are the reactions, with this info you can solve the problem. 1) http://goo.gl/w1Fce 2) http://goo.gl/N9FJ7 3) http://goo.gl/CEUq3

OpenStudy (inkyvoyd):

@open_study1 , I have no idea...

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