Question

10 < –3x + 1
solve show work

Answer 1

\[10 < –3x + 1\]

\[9 < –3x\]
\[9/3 < –x\]
\[3< –x = -3 > x\]

Answer 2

Easily done:
3x < -9
x < -9/3
x < -3

Answer 3

You don't need to.

Answer 4

Yes You Do When you Divide By A Negative Number You Always Flip The Inequality .

Answer 5

Yes you need, and he did it. =)

Answer 6

So the answer is -3 >x?

Answer 7

Yes, try giving values for X starting at -3. And then give lower values (-4, -5, etc) and you will see that it always true. Then give higher values (-2, -1, 0, 1, 2) and you will see that is never true.