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OpenStudy (kropot72):
Is this it?
\[\sqrt[6]{8a \times 3b \times12}\]
OpenStudy (anonymous):
its with \[\sqrt[6]{8a ^{3}b ^{12}}\]
OpenStudy (anonymous):
the first number is a 6 on top
OpenStudy (kropot72):
\[\frac{6}{\sqrt{8a ^{3}b ^{12}}}\]
OpenStudy (anonymous):
so that they way u answer the question?
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OpenStudy (anonymous):
i didnt mean a 6 on top like dividing just its was to let u know it was a 6 before the \[\sqrt{?}\]
OpenStudy (anonymous):
you mean the 6th root?
OpenStudy (anonymous):
\[2^{1/2} a ^{1/2} b^{2}\]
OpenStudy (anonymous):
or \[b ^{2}\sqrt{2a}\]
OpenStudy (anonymous):
cortez how did you get that answer cause it was right and idk how to do it
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OpenStudy (anonymous):
which answer?
OpenStudy (anonymous):
the second one that cortez had put
OpenStudy (anonymous):
@iChristiannnn you basically divide the powers of whatever is under the radical sign by 6.
OpenStudy (anonymous):
and in second case:
a^1/2 is the same as sqrt(a)
OpenStudy (anonymous):
\[-x ^{3}/\sqrt{7x+10}\] how would i rationalize the denominator
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OpenStudy (anonymous):
You can multiply the equation in a \[\sqrt{7x+10} \div \sqrt{7x+10}\] To rationalize the denominator.
\[\sqrt{7x+10} \div \sqrt{7x+10} = 1\] so it won't affect on your result.