Need help with Rationalize denominators
Is this it? \[\sqrt[6]{8a \times 3b \times12}\]
its with \[\sqrt[6]{8a ^{3}b ^{12}}\]
the first number is a 6 on top
\[\frac{6}{\sqrt{8a ^{3}b ^{12}}}\]
so that they way u answer the question?
i didnt mean a 6 on top like dividing just its was to let u know it was a 6 before the \[\sqrt{?}\]
you mean the 6th root?
\[2^{1/2} a ^{1/2} b^{2}\]
or \[b ^{2}\sqrt{2a}\]
cortez how did you get that answer cause it was right and idk how to do it
which answer?
the second one that cortez had put
@iChristiannnn you basically divide the powers of whatever is under the radical sign by 6.
and in second case: a^1/2 is the same as sqrt(a)
\[-x ^{3}/\sqrt{7x+10}\] how would i rationalize the denominator
You can multiply the equation in a \[\sqrt{7x+10} \div \sqrt{7x+10}\] To rationalize the denominator. \[\sqrt{7x+10} \div \sqrt{7x+10} = 1\] so it won't affect on your result.
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