Check My Work? f(x)-(x-2)^3. Is x

Question

Check My Work?

f(x)>-(x-2)^3.  Is x<2?

anonymous · Answer

What is the equation for f(x)?

anonymous · Answer

f(x)>-(x-2)^3 or  0 > –(x – 2)^3

anonymous · Answer

if it's 0 > -(x-2)^3 then x-2>0 so x>2

Why? Because a negative value ^3 will be negative. 2 negatives result in positive and positive > 0 which is not what we want.

anonymous · Answer

But if we test the origin, 

f(x)=0, and x=0. then it is false...

anonymous · Answer

Or am I completely missing it?

anonymous · Answer

what does 
$$f(x)>-(x-2)^3$$ mean?

anonymous · Answer

Find the solutions to 0 > –(x – 2)^3 by graphing f(x) > –(x – 2)^3 by hand.

anonymous · Answer

we aren't including x = 0 as an option. we are using x < 0; but anyways your question is incomplete, you haven't told us what f(x) is. my answer was regarding f(x) = 0

anonymous · Answer

ok now that last post makes some sense

anonymous · Answer

The exact question is "Find the solutions to 0 > –(x – 2)3 by graphing f(x) > –(x – 2)3 by hand."

anonymous · Answer

sorry 
$$0>-(x-3)^2$$ makes sense, we can solve for $x$ but 
$$f(x) > –(x – 2)^3$$ makes no sense. 
maybe it is graph 
$$f(x)=-(x-2)^3$$

anonymous · Answer

Yeah, sorry...

anonymous · Answer

we can solve 
$$0>-(x-2)^3$$ using algebra

anonymous · Answer

I have the same opinion as satellite

anonymous · Answer

$$0>-(x-2)^3$$
$$(x-2)^3>0$$
$$x-2>0$$
$$x>2$$

anonymous · Answer

I didnt even know you could do that... that makes sense!!! Thanks!!!

anonymous · Answer

yw