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Determine the zeros of f(x) = x^3 - 3x^2 - 16x + 48.
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X=3 , 4 , -4
Thank you!
How did you get the answer, though? I'm a bit confused and would like to know how work it out myself so I can do more problems like it.
Easiest and fastest way to do it is to graph it. If you got a calculator that supports graphs, then just input " x^3 - 3x^2 - 16x + 48 " as y1 and 0 as y2 and check where they hit eachother on the graph. Or solve as a 3rd degree equation: http://itsme.home.xs4all.nl/projects/math/misc/solveEquations.html
Okie dokie, sounds good.
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