Question

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Look at question 21 then tell me how to solve it

Answer 1

\[(3x^{-1})^2 \div 6x^{-3}\]

Answer 2

\[(3x^{-1})^2 \div 6x^{-3}\]
\[(\frac{3}{x})^2 \div \frac{6}{x^3}\]
\[(\frac{9}{x^2}) \times \frac{x^3}{6}\]
\[\frac{3}{2}x\]

Answer 3

understand?

Answer 4

can u write plz in words the steps if u want to do it??

Answer 5

\[(3x^{-1})^2 \div 6x^{-3}\]
\[\text{Rewrite the x as, } x^{-1}=\frac{1}{x} ~~,~~6x^{-3}=6\frac{1}{x^3}\]
\[(\frac{3}{x})^2 \div \frac{6}{x^3}\]

Answer 6

\[(\frac{3}{x})^2 \div \frac{6}{x^3}\]
\[\text{Squaring outside the brackets is the same as squaring inside the brackets}\]
\[(\frac{3}{x})^2\div \frac{6}{x^3} =\frac{3^2}{x^2}\div \frac{6}{x^3}\]

Answer 7

thank u

Answer 8

\[\frac{3^2}{x^2}\div \frac{6}{x^3}\]
Flip the sign changes the numerator and denominator
\[\frac{3^2}{x^2}\times \frac{x^3}{6}\]