Solve
ick
what
it is ugly you have to add on the right first
\[\frac{4x+1}{12}+\frac{2x+2}{2x+1}\] \[\frac{(4x+1)(2x+1)+12(2x+2)}{12(2x+1)}\] \[\frac{8x^2+30x+25}{12(2x+1)}\] then \[\frac{2x-1}{6}=\frac{8x^2+30x+25}{12(2x+1)}\]
at least we can multiply both sides by 6 and get \[2x-1=\frac{8x^2+30x+25}{4x+2}\] then \[(2x-1)(4x+2)=8x^2+30x+25\] and now we are ready to solve
\[8x^2-2=8x^2+30x+25\] \[-2=30x+25\] \[-28=30x\] \[x=-\frac{28}{30}=-\frac{14}{15}\] hhmm i wonder if there is an easier way, or if i made mistake
damn i made a mistake!
idk
\[-2=30x+25\] \[-27=30x\] \[x=-\frac{27}{30}=-\frac{9}{10}\]
Ha thats the answer I put .. I just guessed lol
multiple choice?
yupp
lol trust, yet verify http://www.wolframalpha.com/input/?i=%284x%2B1%29%2F12%2B%282x%2B2%29%2F%282x%2B1%29%3D%282x-1%29%2F6
you put 'solve' in-front of the expression , you can even get the steps :D
very rectangular
?
@.Sam. true, but that is the way a machine solves it. i am not a human would have solved it that way
notice all the fractions
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