Question

Factor by grouping equation is
(4g2 + 12gh + 5g + 15h)?

Answer 1

take the first two terms and remove the common out ... then the last two

Answer 2

(4g2+12gh)+(5g+15h)
4g(gh+3h)+5(g+3h)
not sure this is correct but its as far as i can go

Answer 3

is simple

Answer 4

i have a extra h in the first part sorry

Answer 5

\[\Large 4g(g+3h)+5(g+3h)\]

Answer 6

then remove the common (g+3h) out

Answer 7

so its (g + 3h)(4g + 5)? thats the answer right?

Answer 8

would this turn to
(4g+5) (g+3h)^2

Answer 9

yes :) @alamojoe9

Answer 10

no ^2

Answer 11

(4g-5h)(g+3) ya that is correct

Answer 12

thanks!

Answer 13

but dont you have to account for both (g+3h)

Answer 14

the first one poster was the right one which is "so its (g + 3h)(4g + 5)"

Answer 15

@Nismo450Z
let, \(\large(g+3h) = P\)
\[a \cdot P +b \cdot P =(a+b)P\]

Answer 16

now i see i will keep that in mind thanks