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Mathematics 15 Online
OpenStudy (anonymous):

Evaluate In 5.

OpenStudy (anonymous):

The question is evaluate In 5

OpenStudy (anonymous):

It's a log of base e, which is called a natural log. I just have no idea how to solve it.

OpenStudy (anonymous):

natural log.

OpenStudy (ash2326):

@dmartinez130 We could use log tables for this but if you know some standard logs then we can evaluate this. Do you want to know?

OpenStudy (anonymous):

Yes please.

OpenStudy (anonymous):

Just plug it in the calculator. You have sufficient information on how logs and natural logs work

OpenStudy (anonymous):

I don't have a calculator that has log on it.

OpenStudy (anonymous):

you need a calculator with log10 or ln they are cheap. probably even your cellphone has it.

OpenStudy (anonymous):

how 'bout the computer calculator...???

OpenStudy (ash2326):

We know \[\ln 10=2.303\] and \[\log_{10} 10=1\] and \[\log_{10} 2=0.3010\]

OpenStudy (anonymous):

if she takes a test she wont be able to use PC

OpenStudy (ash2326):

Let's use these to find \(\ln 5\) @dmartinez130 do you know the logarithmic property \[\log_a b=\frac{\log_c b}{\log_c a}\] ?

OpenStudy (ash2326):

\[\ln 5= \frac{\log_{10} 5}{\log_{10} e}\] \[\ln 5= {\log_{10} 5}\times {\log_{e} 10}\] \[\ln 5= {\log_{10} {\frac{10}2}} \times 2.303 \ ( since\ \log_e 10=\ln 10=2.303)\] \[\ln 5= (\log_{10} -\log_{10} 2) \times 2.303\] \[\ln 5= (1-0.3010) \times 2.303\] I think you can evaluate now?

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