Ask your own question, for FREE!
Physics 17 Online
OpenStudy (anonymous):

Calculate the net charge on a substance consisting of a combination of 5.5 × 10^13 protons and 1.2 × 10^13electrons. I tried -1.62279x10^20 but seemed don't work for me.

OpenStudy (anonymous):

@Mkz , tell me what happens when 1 proton + 1 electron ?

OpenStudy (anonymous):

@Mkz , there ??

OpenStudy (anonymous):

o

OpenStudy (anonymous):

repel

OpenStudy (anonymous):

repel ??

OpenStudy (anonymous):

yeah..

OpenStudy (anonymous):

1 proton + 1 elctron = no charge. (they don't repel) So now tell me in your question which is greater, number of proton or number of electron ??

OpenStudy (anonymous):

proton..

OpenStudy (anonymous):

4.3x10^13 protons

OpenStudy (anonymous):

Yes. Now 1.2 × 10^13electrons + 1.2 × 10^13protons neutralize and charge becomes zero. Therefore Number of protons-->you told above Now multiply the number of protons by 1.6 * 10^{-19} to get your answer

OpenStudy (anonymous):

multiply?

OpenStudy (anonymous):

6.88x10^-6?

OpenStudy (anonymous):

yes boss

OpenStudy (anonymous):

thx any way the online quest freak out now

OpenStudy (anonymous):

why multiply ? Because 1 proton contains 1.6*10^(-19) charge therefore 4.3x10^13 protons contain ?? Therefore 4.3x10^13 protons contain 4.3x10^13 * 1.6*10^(-19} charge

OpenStudy (anonymous):

yw :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!