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Mathematics 19 Online
OpenStudy (anonymous):

Simplify √(12/49)

OpenStudy (anonymous):

(2/7) root 3.

OpenStudy (asnaseer):

\[\sqrt{\frac{12}{49}}=\frac{\sqrt{12}}{\sqrt{49}}\]

OpenStudy (asnaseer):

now you should be able to simplify \(\sqrt{49}\) first - do you know what the answer to this will be?

OpenStudy (anonymous):

yes 7

OpenStudy (asnaseer):

correct, next we can write \(\sqrt{12}\) as:\[\sqrt{12}=\sqrt{4*3}=\sqrt{4}*\sqrt{3}\]

OpenStudy (asnaseer):

so here you should be able to simplify the \(\sqrt{4}\) term - what will that be?

OpenStudy (anonymous):

why did you do that?

OpenStudy (anonymous):

isnt your suppose to facotr the 12?

OpenStudy (asnaseer):

when you get a square root of something that itself is not a perfect square, then you should try and decompose it into the product of something which is a perfect square and something else

OpenStudy (anonymous):

so isnt it 2x2x3?

OpenStudy (anonymous):

the factors

OpenStudy (asnaseer):

so, since 12 is not a perfect square, we set it to be 4*3 because 4 is a perfect square

OpenStudy (asnaseer):

you could set 12=2*2*3, but that is unnecessary

OpenStudy (anonymous):

oh ok so what do you do after that

OpenStudy (asnaseer):

the idea here is to find "perfect squares" in order to simplify the expression

OpenStudy (anonymous):

so how would you find the answer?

OpenStudy (anonymous):

what is the final answer in this case

OpenStudy (asnaseer):

ok, the last step was:\[\sqrt{12}=\sqrt{4*3}=\sqrt{4}*\sqrt{3}\]and I asked you what the value of \(\sqrt{4}\) would be?

OpenStudy (anonymous):

2

OpenStudy (asnaseer):

correct, so now we put all the pieces together to get:\[\sqrt{49}=7\]\[\sqrt{12}=2\sqrt{3}\]therefore:\[\sqrt{\frac{12}{49}}=\frac{\sqrt{12}}{\sqrt{49}}=\frac{2\sqrt{3}}{7}\]

OpenStudy (anonymous):

ohhh i see now thank you so so so much!

OpenStudy (asnaseer):

yw :)

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