Evaluate (1/2!)+(2/3!)+(3/4!)+...(n/(n+1)!). Conjecture the sum if n tends to infinity.
With some summation manipulation, we can come up with a formula for the sum of the first n terms. Then we just need to take the limit as n goes to infinity for our answer. Note that this isnt the way they want you to solve the problem. They want you to compute a couple of sums by hand (maybe up to the first 7 terms or so) and guess what the limit might be as n goes to infinity.
yes, as joemath says, try working out some partial sums and you may be able to spot the pattern.
So what we have to deal with is the sum of the first n terms which is:\[\sum_{k=0}^n\frac{k}{(k+1)!}\]I suggest maybe changing the k to (k+1)-1, simplifying, and see if you can guess what the formula for the sum of the first n terms is. Again, this is not required. You should be able to guess my computing a couple of sums by hand. The method I propose will actually give you the answer without guessing.
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