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Mathematics 15 Online
OpenStudy (anonymous):

There are three doors. one doors have money and two has nothing. I pick door two. Door one opens and it empty. If i switch to door three what % chance do I have getting the money door.

OpenStudy (anonymous):

Anyone know?

OpenStudy (unklerhaukus):

if you switch you have a 1/2 chance of prize if you do not switch you have a 1/3 chance of prize

OpenStudy (anonymous):

Incorrect

OpenStudy (unklerhaukus):

why incorrect?

OpenStudy (anonymous):

They were not the right percents. P.s. its not because they were in fraction form.

OpenStudy (unklerhaukus):

would you accept 50% and 33.3%

OpenStudy (anonymous):

They are incorrect.

OpenStudy (unklerhaukus):

ok well i still dont see why , do you have evidence to suggest otherwise?

OpenStudy (anonymous):

2/3?

OpenStudy (lgbasallote):

lol Monty Hall principle...just saying

OpenStudy (anonymous):

Jazy is correct.

OpenStudy (unklerhaukus):

but that is only a single fraction

OpenStudy (accessdenied):

Three scenarios: - You choose one of the two 'nothing.' The other door reveals nothing and you switch to the money. - You choose the other 'nothing' and the first 'nothing' is revealed. You switch to the money. - You choose the money and nothing is revealed, and switch to nothing, losing. Of course, you win 2/3 of the time in this set up.

OpenStudy (kinggeorge):

If door 1 was opened intentionally BECAUSE it had nothing behind it, you increase your odds to 2/3 if you switch. If it was just opened, you actually still have 1/2 chance with both doors available to you.

OpenStudy (anonymous):

Its the Monty Hall principle :)

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