Question

Solve the equation 5/4x-x=2

Answer 1

\[\large \frac{5}{4x} or \frac{5}{4}x\]

Answer 2

Is it incorrect to multiply across by 4x?

Answer 3

Or..
\[\large \frac{5}{4x-x} =2\]?

Answer 4

depends...you might wanna tell us which is which first

Answer 5

\[5\over4x \]

Answer 6

Sorry for the confusion!

Answer 7

\[\large \frac{5}{4x} -x=2\]??

Answer 8

Yes

Answer 9

Write it as:
\[\frac{5}{4x}-\frac{x}{1} =2\]
then times the top and bottom by \(4x\) for it to common.

Answer 10

\[20x-4x^{2} = 8x\]

Answer 11

Correct!
Do you know what to do next?
You can use the quadratic formula to solve for \(x\)

Answer 12

Yeah, i got \[4x^2 + 20x - 8x = 0\] then divided across by 2. Minus B formula, it shouldnt be whole numbers right?

Answer 13

X = 19.5 discard the negative value?

Answer 14

I don't think that it's \(4x^2+2x-8x=0\) since when the equation was \(5-4x^2=8x\) you move the \(8x\) to the left..

Answer 15

4x^2+20x−8x=0?

Answer 16

if you multiply 5/4x by 4x, 4x cancels but you still multiply by the 5?

Answer 17

It's \(4x^2+8x-5=\)

Answer 18

AH! i made a fundamental mistake, :(

Answer 19

\(4x^2+8x-5=0\)*

Answer 20

Thank you mimi :)

Answer 21

wait where did you get the \(20\) from?

Answer 22

I thought you must multiply above & below the line in the fraction, or \[4x \times 5/4x\] so when the 4x cancelled, i multiplied the 5 by 4x! :(

Answer 23

I think that I confused you; sorry.
\[\frac{5}{4x}-\frac{x*4x}{1*4x} =2 =>\frac{5}{4x} -\frac{4x^{2}}{4x} =2 =>\frac{5-4x^{2}}{4x} =2\]

Answer 24

Do you get it now?

Answer 25

Yeah! Thanks so much for your time :)

Answer 26

Np (: