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What is the 7th term of the geometric sequence where a1 = -2 and a5 = -512?
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find the common ratio using the formula \[\Large A_n = A_1 r^{n-1}\] let \(\large A_n = A_5\) \[\Large A_5 = A_1r^{5-1}\] i've done enought..you do the rest :D
ok thanks
you know what to do after you get the r right?
ill try
okay :0
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:)
yeah that was supposed to be a :) too lol
u know how hoblos to do this? What is the 7th term of the geometric sequence where a1 = -2 and a5 = -512?
a5 = a1*r^4 r^4 = a5/a1 = 512/2 = 256 so r = fourth-root(256) = 4 a7 = a1*r^6 = (-2)*(4)^6 = -2(4096) = -8192
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