Question

Find the quotient.

42j^4k^2 ÷ (-3j^3k)

-14jk
14jk
-14j²k

Answer 1

anyone know

Answer 2

\[\large \frac{42j^4k^2}{-3j^3k}\]
Let's cancel the common terms
\[\large \frac{42j^{\cancel{4}1}k^{\cancel{2}1}}{-3\cancel{j^3}\cancel k}\]
\[\large \frac{42 jk}{-3}\]
\[-\large \frac{\cancel{42}14 jk}{\cancel{3}}\]
so we get finally
\[\huge -14jk\]

Answer 3

ok thank you

Answer 4

Do you understand?

Answer 5

kinda

Answer 6

ya i do