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OpenStudy (anonymous):
what is the minimum y-value for the following relation. (x-2)^2 + (y+12)^2 = 10^2
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OpenStudy (anonymous):
Differentiate then find the critical points by setting the differential of f to zero. Then differentiate the differential to get the second differential and plug in your values to check the concavity of the graph at those points. If the second differential is greater than zero then the group would be concave upward. Therefore it would be a minimum point. Note that you'll have to differentiate this equation implicitly.
OpenStudy (anonymous):
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OpenStudy (anonymous):
@mertsj can you help me?
OpenStudy (anonymous):
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