The baseball coach is going to pick 9 players for the team. He has 9 outfielders, 10 infielders, and 4 pitchers to pick from. The team must have 3 outfielders, 1 pitcher, and 5 infielders. How many ways can he select his baseball team? i dont know how to solve someone show me pls
You just do the three problems separately, and multiply your results: So, there are "9 choose 3" ways to get the outfielders, "4 choose 1" (which is just 4) ways to get the pitcher, and "10 choose 5" ways to get the infielders. Whatever 3 numbers you get, you multiply, and that will give you all the possibilities. And just in case you don't know, n choose k is denoted by, and means,\[\left(\begin{matrix}n \\ k\end{matrix}\right) = {n! \over k!(n-k)!}\]
could you multiply them all?
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