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convert the polar coordinates r=4,theta= (10pi)/3 to rectangular coordinates in the xy-plane
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\(x=r \cos \theta\) \(y=r\sin \theta\)
We just use x = rcos(theta) and y = rsin(theta) 10pi/3 is equivalent to 4pi/3, so x = 4 (cos(4pi/3)) = 4*(-1/2) = -2 y = 4 (sin(4pi/3) = 4*(-sqrt(3)/2) = -2sqrt(3) So, the point is at (-2,-2sqrt(3))
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