Question

find an equivalent equation in retangular form for r-6sin=2cos

Answer 1

\[ r- 6 \sin \theta= 2 \cos \theta\]
Is this your question
???

Answer 2

ye

Answer 3

convert to rectangular fform

Answer 4

You mean the form
\[a+ib\]

Answer 5

no like x^2 + y^2 form

Answer 6

Ok, I got it
\[r= 6 \sin \theta+ 2\cos \theta\]
divide and multiply right hand side by by \(\sqrt{6^2+2^2}\)
\[r=(6 \sin \theta+ 2\cos \theta)\times \frac{\sqrt {40}}{\sqrt {40}}\]
\[r=\sqrt{40}(\frac 6{\sqrt 40} \sin \theta+ \frac 2{\sqrt {40}}\cos \theta)\]
\[r=\sqrt {40} \sin ( \theta +x)\ \text{ where x=}\ \tan^{-1} \frac{2}{6}\]

Answer 7

@curry Is this the form you need ?

Answer 8

well ssomewhat in other word in the simplified form no r sshould be preent nor any sin or coss

Answer 9

Is your
\[r=x+iy\]
?

Answer 10

here is my work
r = 2cos+6sin
r^2=2rcos+6rsin
x^2+y^2=2x+6y

Answer 11

i jussst dont get where to go from there

Answer 12

You've done great
\[x^2+y^2-2x-6y=0\]
This is your rectangular equation

Answer 13

@Curry I just realized that you've posted this in Biology. Please use maths for Maths' questions

Answer 14

Hi Curry, please post math questions in the math group. Helps you get better answers (though Ash has given you a superb one) and helps us keep the site organised. Here is the link: http://openstudy.com/study?login#/groups/Mathematics.

Thanks.