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Mathematics 19 Online
OpenStudy (anonymous):

How do you tell if something is a exponential decay or not?

OpenStudy (anonymous):

If the amount that it decays per second is a function of how much stuff there is at that moment, then it can be expressed as E.D.

OpenStudy (campbell_st):

got exponential growth... the constant k is positive, for decay its negative growth model \[A = Pe^{kt}\] decay model \[A=Pe^{-kt}\] hope this helps

OpenStudy (anonymous):

But if you are given\[A=Pb ^{kt}\] where b is a constant, you can convert it into\[A=Pe ^{kt}\]

OpenStudy (campbell_st):

the other test to see if it is exponential is to differentiate and seek that the derivative is a proportional to the model e.g for the growth model \[A=Pe^{kt}\] \[\frac{dA}{dt} = kPe^{kt}\] which can be written in terms of the original model \[\frac{dA}{dt} = k(Pe^{kt}) = kA\]

OpenStudy (anonymous):

still confused but ill youtube it thanx guys

OpenStudy (anonymous):

http://www.youtube.com/watch?v=HTDop6eEsaA He's always good

OpenStudy (anonymous):

if b is greater than 0 but less than 1, then it is decay....

OpenStudy (anonymous):

because.. b^k = (1/b)^(-k). so if 0<b<1, the equation will be a decay.

OpenStudy (anonymous):

still need help?

OpenStudy (anonymous):

It will also decay (no matter what b is) if k is negative.

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