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The area of a given hexagon is equal to the area of an equilateral triangle whose perimeter is 36 inches. Find the length of a side of the regular hexagon.
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|dw:1337460750707:dw| Here, the 2 similar equilateral triangle have Area scale factor 6, so linear scale factor root(6), so the length is 12*(1/root6)=2root6. I may be wrong.
Solve for x in: \[ \frac{\sqrt{3}} 4 \times (12)^2 = \frac{\sqrt{3}} 4 \times x^2 \times 6 \]
\(\implies x= 2\sqrt{6}\)
So, @henpen is right.
Area of the equilateral triangle of perimeter 36 is \( \frac{\sqrt{3}} 4 \times (12)^2 \)
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Simmilary area of an equilateral triangle is given by \(\frac{\sqrt{3}} 4 \times x^2 \times 6\)
where x is the side length.
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