Riddle me this , can somebody show me step by step on how to get 10/3 , from a over b+c if a/b=5;b/c=2
maybe restructure it so that everything speaks in terms of b
you've already asked this question here: http://openstudy.com/users/thx1138#/updates/4fb80862e4b05565342d6e40 if the explanations were not clear then you should have asked for more explanation in that question rather than closing it and reposting the same question.
yes, that would have been the best thing to do.
Then can one of you please clear it up for me?
i cant read your mind so i dont know how this can NOT possibly be clear as it stands :/ you are going to have to be more specific in your perplexities
this was the explanation given by @rs32623 in the other question: from a/b=5 we have a=5b from b/c=2 we have c=b/2 now for a/(b+c) we have 5b/(b+b/2)=10/3 is that that the answer? i assumed it a/(b+c) rather than a/b + c --- which part of this do you want more explanation on?
the original problem is written as a/b+c , I still get 7/10 that is why I asked to have it cleared up, I thought I had but I dont.
do you agree that it can be reduced to the following?\[\frac{a}{b+c}=\frac{5b}{b+\frac{b}{2}}\]
thats as far as i got then i got lost.
ok, let me take you through it from this point on...
please.
\[\frac{a}{b+c}=\frac{5b}{b+\frac{b}{2}}=\frac{5b}{\frac{2b}{2}+\frac{b}{2}}=\frac{5b}{\frac{3b}{2}}=5b\div\frac{3b}{2}=5\cancel{b}\times\frac{2}{3\cancel{b}}=\frac{10}{3}\]
thats a little clearer I have to learn how to input fractions on this web site. thank you
this uses the fact that:\[x\div\frac{y}{z}=x\times\frac{z}{y}\]
there is a latex practising group that might help you - there are lots of tips there (mostly in the closed questions)
here is the link to it: http://openstudy.com/study?login#/groups/LaTeX%20Practicing!%20%3A)
great thanks
yw
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