Question

I've solved all of these problems already except for 4.. I'm really stuck but I would seriously appreciate it if the answers were provided so i could see if my work is right. I'm including the answers I got.

Answer 1

\[3(9^{x})-3^{x}=0\]
\[e ^{2x}+7e ^{x}=-12\]
\[\log_{4}x+\log_{4}(2x+1)=2 \]
\[\ln(5x+1)=\ln(2x)+\ln2\]
\[\log_{3}(x ^{2} )+\log_{9} (3)=\log_{27}(x) \]

Answer 2

my answers were:

1. -1
2. No Solution
3. 2.589
4. I got stuck on this one
5. 0.7192

Answer 3

\[\Large e^{\ln(5x+1)} = e^{\ln(2x) + \ln(2)}\]
\[\Large 5x+1 = e^{\ln(2x)}e^{\ln(2)}\]
\[\Large 5x+1 = 2x*2\]
Understand?

Answer 4

So that way they cancel right?

Answer 5

So x is -1?

Answer 6

Good.

Answer 7

Number 3 is correct, but you should have gotten multiple solutions.

Answer 8

Yeah one was negative but you can't have a negative answer.

Answer 9

Ah, good call =)

Answer 10

Extraneous solution.

Answer 11

all the rest of answers right?