What is the domain of f(x)= 1/x ?
Okay domain means the acceptable values of 'x' in the function, right? Now, what is one value 'x' can't take in here - that is one value where the function is undefined?
all real numbers except the value of x that will make the function undefined...what do you think will make it undefined?
hmm coincidence @apoorvk -_-
Need a hint? Okay - "1/0" is undefined.
I know it can't be 0 I'm just not sure how to right it out.
write*
Yeah you are right - 'x' can't be zero. Okay so you want to learn the notations of how to write the range right?
**i mean the 'domain', sorry.
Yes
domain - all real numbers except 0
So you write \[\large x \in (-\infty, \infty) - \text{{0}} \] here the 'epsilon' means ---> 'belongs to' (a,b) ---> from 'a' to 'b' (and that 'a' and 'b' are not included) '-' --> EXCEPT {c,d} ---> nos. written curly brackets means that/those particular nos. only --> in this case only c and d. in our case {0} will mean '0' only. So, what I wrote above translates to:- " 'x' BELONGS TO 'negative infinity' TO 'infinity' EXCEPT '0'.
i think some write it as \[ (-\infty , 0) U (0, \infty)\]
Also, you could simply write this as \[x \in R - \text{{0}}\] because basically what we mean is that 'x' can be any real except '0'.
|dw:1337493982925:dw| i think i recall something like that....
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