Question

help calculus 1 integral problem

Answer 1

are my answers correct
a) sin[(pi/2)(1/2)]cos[(pi/2)(1/3)] - sin(0)cos(0) = sin(pi/4)cos(pi/6) -0 =[2^(1/2)/2](1/2) = [2^(1/2)/4]

b) = d/dx(-[2^(1/2)/2][3^(1/2)/2]-0) = -d/dx[6^(1/2)/4 = -0 =0

c)= -d/dx[-cos(x/2)sin(x/3)] =d/dx[cos(x/2)sin(x/3] = -sin(x/2)cos(x/3)

Answer 2

Wait. The first one before substituting the value pi/2, won't it just be sin(x/2)cos(x/3), because if you differinciate and then integrate it you get the same thing?? just checking that that's right. But no, i don't think your first one is right, because it should be sin((pi/2)/2) = sin(2pi/2) = sin(pi).

Answer 3

so, \[\sin (pi) \cos (3pi/2)\]
I really am not sure, just guessing here :P

Answer 4

o right i cant take sin and cos out individually

Answer 5

and you would have to subtract it from sin(0)cos(0), which is basically 0, so i skipped that :P

Answer 6

yes i did that

Answer 7

idk, i got the same answer as my professor on part b and c but not a. he doesnt show work though

Answer 8

so.............next one :P

I think that's right, cuz whatever you integrate, you're gonna get a number, and the derivative of a constant is zero. I'm not bothered to integrate that thing :P

Answer 9

wait nvm, i doubt my professor's answer on a. i think my a is correct because to take out the antiderivative of sin(x/2)cos(x/3), all i have to do is substitute pi/2 into x

Answer 10

he got 6^(1/2)/4 on a

Answer 11

and FINALLY. the third one can't be done, bro. the expression to be integrated has the variable t, and the derivative sign is in "x"

Answer 12

so is the one you posted YOUR answer, or his??

Answer 13

x is a constant on c

Answer 14

the one i posted was my answers for a,b,c. but i have his answers, which are consistent to my b and c, not a tho

Answer 15

ohhh. i'm confused about the last one :P

Answer 16

but wait, like i said for a, you did pi/2 * 1/2, not (pi/2) / (1/2). geddit???

Answer 17

yea i substitute pi/2 into sin(x/2)cos(x/3)

Answer 18

right. aaaand??

Answer 19

so it's sin(pi/2)(1/2) cos(pi/2)(1/3)

Answer 20

which are sin(pi/4)cos(pi/6)

Answer 21

arrey